In a Young-s double slit experiment- the path different- at a certain point on the screen- between two interfering waves is 18th of wavelength- The ratio of the intensity at this point to that at the centre of a brigth fringe is close to -

The correct option is D 0.85 Δ x=λ8 Δϕ=(2π)λλ8=π4 I=I_0cos^2(π8) II_0=cos^2(π8) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Intensity Explanation in YDSE

In a Young's ...

Question

In a Young's double slit experiment, the path different, at a certain point on the screen, between two interfering waves is $\frac{1}{8} t h$ of wavelength. The ratio of the intensity at this point to that at the centre of a brigth fringe is close to :

0.94

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.74

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.85

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.80

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $0.85$
$Δ x = \frac{λ}{8}$
$Δ ϕ = \frac{(2 π)}{λ} \frac{λ}{8} = \frac{π}{4}$
$I = I_{0} {cos}^{2} (\frac{π}{8})$
$\frac{I}{I_{0}} = {cos}^{2} (\frac{π}{8})$

Suggest Corrections

Similar questions

Q. In a Young's double slit experiment, the path difference, at a certain point on the screen, between two interfering waves is

{\frac{1}{8}}^{t h}

of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to:

Q. In a double-slit experiment, at a certain point on the screen the path difference between the two interfering waves is

{\frac{1}{8}}^{th}

of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is

Q. At a certain point on a screen the path difference for the two interfering rays is

{(1 / 8)}^{t h}

of a wavelength. Find the ratio of the intensity at this point to that at the centre of a bright fringe.

At a certain point on a screen in a YDSE apparatus, the path difference for the two interfering waves is ${(\frac{1}{3})}^{r d}$ of the wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is

Q. In Young's double slit experiment, the path difference between two interfering waves at a point on screen is

13.5

times the wavelength. The point is:

Join BYJU'S Learning Program

In a Young's double slit experiment, the path different, at a certain point on the screen, between two interfering waves is 18th of wavelength. The ratio of the intensity at this point to that at the centre of a brigth fringe is close to :

The correct option is D 0.85Δx=λ8Δϕ=(2π)λλ8=π4I=I0cos2(π8)II0=cos2(π8)

In a Young's double slit experiment, the path different, at a certain point on the screen, between two interfering waves is $\frac{1}{8} t h$ of wavelength. The ratio of the intensity at this point to that at the centre of a brigth fringe is close to :

The correct option is D $0.85$
$Δ x = \frac{λ}{8}$
$Δ ϕ = \frac{(2 π)}{λ} \frac{λ}{8} = \frac{π}{4}$
$I = I_{0} {cos}^{2} (\frac{π}{8})$
$\frac{I}{I_{0}} = {cos}^{2} (\frac{π}{8})$