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Question

# In a Young's double slit experiment, the separation between the slits is 0.15 mm. In the experiment, a source of light of wavelength 589 nm is used, and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is:

A
6.9 mm
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B
3.9 mm
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C
5.9 mm
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D
4.9 mm
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Solution

## The correct option is C 5.9 mmGiven that, the distance between screen and slits, D=1.5 m Separation between slits, d=0.15 mm Wavelength of source of light, λ=589 nm The separation between the successive bright fringe on the screen is Fringe width, β=Ddλ=1.50.15×10−3×589×10−9 m β=589×10−5=5.89×10−3 m β=5.89 mm≈5.9 mm Hence, option (C) is correct.

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