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Question

In a Young's double slit experiment, the slits are 2 mm apart and the screen is positioned 140 cm away from the plane of the slits. The slits are illuminated with light of wavelength 600 nm. Find the distance of the third bright fringe from the central maximum.

A
1.26 mm
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B
0.15 mm
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C
3.76 mm
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D
2.97 mm
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Solution

The correct option is A 1.26 mm
Given:
d=2 mm=2×103 m
D=140 cm=1.4 m
λ=600 nm=6×107 m

Distance of nth bright fringe, from the central bright fringe, is
βn,b=nβ=n λDd
Here, n=3
β3,b=3×6×107×1.42×103

β3,b=12.6×104 m=1.26 mm

Hence, (A) is the correct answer.

Why this question :Concept : For bright fringe, the path difference between interfering waves should be integral multiple of wavelength.

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