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Question

In a Young's double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle 140rad by using light of wavelength λ1. When the light of wavelength λ2 is used a bright fringe is seen at the same angle in the same set up. Given that λ1 and λ2 are in visible range (380 nm to 740 nm), their values are

A
380 nm,500 nm
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B
625 nm,500 nm
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C
380 nm,525 nm
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D
400 nm,500 nm
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Solution

The correct option is B 625 nm,500 nm
Path difference =dsinθdθ
=0.1×140mm=2500 nm
or bright fringe, path difference must be integral multiple of λ.
2500=nλ1=mλ2
λ1=625,λ2=500 (from m=5)
(for n=4).

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