In a Young's doubleslit experiment, first maxima is observed at a fixed point P on the screen. Now, the screen is continuously moved away from the plane of slits. The ratio of intensity at point P to the intensity at point O (centre of the screen)
A
remains constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
keeps on decreasing
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
first decreases and then increases
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
first decreases and then becomes constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C first decreases and then increases Position of 1st Maxima:
x=D×λd
As D increases, the Maxima at P will go upwards.
We know that There is a Minima between O and P.
Hence Point P will observe a decrease in intensity till the position of minima is reached and after that the Intensity will increase due to the Central Maxima.