Question

In a zero order reaction for every ${10}^{\circ }C$ rice of temperature, the rate is doubled. If the temperature is increased from ${10}^{\circ }C$ to ${100}^{\circ }C$, the rate of the reaction will become:

• A. 256 times
• B. 512 times
• C. 64 times
• D. 128 times

Answer 1

The correct option is B 512 times

For ${10}^{\circ }$ rise in temperature, n =1
So rate $=2^n=2^1=2$
When temperature is increased from ${10}^{\circ }C$ to ${100}^{\circ }C$, change in temperature
$=100-10={90}^{\circ }C$
i.e.so, rate =$2^9=512$ times
alternate method with every ${10}^{\circ }$ rise in temperature, rate becomes double.
So $\frac{r^{\prime }}{r}=2(100-\frac{10}{10})=2^9=512$ times