In - ABC - - A -60- - Prove that BC 2- AB 2- AC 2- AB - AC -

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Pythagoras Theorem

In Δ ABC , ∠ ...

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In ∆ABC, ∠A = 60°. Prove that BC² = AB² + AC² − AB . AC.

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Δ A B C, ∠ A B C = 135^{\circ}

A C^{2}

A B^{2}

B C^{2}

4 (Δ A B C)

△

∠ A = 60

{B C}^{2} = {A B}^{2} + {A C}^{2} - A B \cdot A C

Δ A B C

B

A B^{2} + B C^{2} = A C^{2}

△ A B C, ∠ A B C = 135^{o}

{A C}^{2} = {A B}^{2} + {B C}^{2} + 4 A (△ A B C)

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