Question

In $∆$ABC, AB = 5 cm, BC = 8 cm. AC = 10 cm. Then find the smallest and the biggest angle of triangle and arrange the angles in the descending order of their measures.

Answer 1

$$\begin{gathered} \mathrm{Given}:\text{In}△\mathrm{ABC},\mathrm{AB}=5\mathrm{cm},\mathrm{BC}=8\mathrm{cm},\mathrm{AC}=10\mathrm{cm} \\ \mathrm{Since}\text{the}\mathrm{angle}\mathrm{opposite}the\mathrm{largest}\mathrm{side}\mathrm{is}\mathrm{biggest}\mathrm{and}\mathrm{that}\mathrm{opposite}\text{the}\mathrm{smallest}\mathrm{side} \\ \mathrm{is}\mathrm{smallest},\angle \mathrm{B}\text{is}\mathrm{the}\mathrm{greatest}\mathrm{angle}\mathrm{and}\angle \mathrm{C}\text{is}\mathrm{the}\mathrm{smallest}. \\ \mathrm{The}\mathrm{angles}\mathrm{in}\mathrm{descending}\mathrm{order}\mathrm{are} \\ \angle \mathrm{B}>\angle \mathrm{A}>\angle \mathrm{C} \end{gathered}$$