In ∆ABC, AB = AC and ∠B = 50°. Then, ∠C = __________.

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Solution

In ∆ABC,

AB = AC (Given)

∴ ∠C = ∠B (Angles opposite to the equal sides of a triangle are equal)

⇒ ∠C = 50° (∠B = 50°)

In ∆ABC, AB = AC and ∠B = 50°. Then, ∠C = 50°.

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Similar questions

$I n Δ A B C, AB = AC and ∠ B = 50^{\circ} . T h e n ∠ A = ? (a) 40^{\circ} (b) 50^{\circ} (c) 80^{\circ} (d) 130^{\circ}$

Δ A B C

∠ B = 50^{\circ}

∠ C

40^{\circ}

50^{\circ}

80^{\circ}

130^{\circ}

Δ A B C, A B = A C

∠ A = 70^{o} .

∠ B

∠ C .

Δ A B C

A B = A C

∠ C = ∠ B

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