In Delta- ABC and Delta-DEF- ang-A - ang-E- 50- AB-ED - AC-EF and- ang-F - 65- Show that AB - AC

Dear student, In triangle DEF, Angle E = 40 deg; Angle F = 65 deg; Angle D = 180 (40+65) nbsp; (ASP of a triangle) = 180 105 = 75 deg; Angle D = Angle ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Angles in Same Segment of a Circle

In Delta; ...

Question

In Δ ABC and ΔDEF, ∠A = ∠E= 50, AB/ED = AC/EF and, ∠F = 65. Show that AB = AC

Open in App

Solution

Dear student,

In triangle DEF,
Angle E = 40°

Angle F = 65°

Angle D = 180-(40+65) (ASP of a triangle)

= 180-105

= 75°

Angle D = Angle B (SAS congruency)

therefore,

B = 75°

Regards.

Suggest Corrections

Similar questions

In $△$ ABC and $△$ DEF, $∠$ A = $∠$ E = $40^{\circ}$ and $\frac{A B}{E D}$ = $\frac{A C}{E F}$ . Find $∠$ B if $∠$ F is $65^{\circ}$ .

Q. In triangles ABC and DEF, ∠A = ∠E = 40°, AB : ED = AC : EF and ∠F = 65°, then ∠B =

(a) 35°
(b) 65°
(c) 75°
(d) 85°

In $Δ A B C$ and $Δ D E F$ , $∠ A = ∠ E = 40^{\circ}$ , AB : ED = AC : EF and $∠ F = 65^{\circ}$ , then the value of $∠ B$ is

Q. In

Δ

ABC and

Δ

DEF, AB

=

DE, AB

| |

DE, BC

=

EF and BC

| |

EF. Vertices A, B and C are joined to vertices D, E and F respectively. Show that AC

=

DF.

Join BYJU'S Learning Program

In Δ ABC and ΔDEF, ∠A = ∠E= 50, AB/ED = AC/EF and, ∠F = 65. Show that AB = AC

Dear student, In triangle DEF, Angle E = 40° Angle F = 65° Angle D = 180-(40+65) (ASP of a triangle) = 180-105 = 75° Angle D = Angle B (SAS congruency) therefore, B = 75° ​​​​​​​Regards.

Dear student,

In triangle DEF,
Angle E = 40°

Angle F = 65°

Angle D = 180-(40+65) (ASP of a triangle)

= 180-105

= 75°

Angle D = Angle B (SAS congruency)

therefore,

B = 75°

Regards.