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Question

In ∆ABC and ∆DEF, we have: ABDE=BCEF=ACDF=57, then
ar(∆ABC) : ar(∆DEF) = ?

(a) 5 : 7
(b) 25 : 49
(c) 49 : 25
(d) 125 : 343

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Solution

(b) 25 : 49
  • In ABC and DEF, we have:ABDE = BCEF = ACDF = 57Therefore, by SSS criterion, we conclude that ABC~DEF. ar(ABC)ar(DEF) = AB2DE2 = 572 = 2549 = 25 : 49

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