In ABC ,Given that DE//BC , D is the midpoint of AB and E is a midpoint of AC. The ratio AE : EC is ____.
1:1
DE is parallel to BC
So, In triangles ABC , ADE
∠DAE = ∠ECF {Alternate angles}
∠ADE = ∠EFC {Alternate angles}
∠BAC = ∠DAE
By A.A.A similarity ABC≡ADE
⇒ADDB=AEEC ( Basic Proportionality Theorem )Since, D is midpoint of AB .AD=DB⇒ADDB=11=AEEC⇒AEEC=1
ALTERNATE SOLUTION
D is the midpoint of AB. A line segment DE is drawn which meets AC in E and is parallel to the opposite side BC.
BCFD is a parallelogram DF || BC and CF || BD
CF = BD {opposite sides of parallelogram are equal}
CF = DA {Since BD = DA given}
In △ ADE and △ CFE
AD = CF
∠DAE = ∠ECF {Alternate angles}
∠ADE = ∠EFC {Alternate angles}
△ ADE ≡ △ CFE
AE = EC {Corresponding parts of congruent triangles are equal}
AE: EC = 1: 1
In triangles ADE