In ∆ABC, if AB = 16 cm, BC = 12 cm and AC = 20 cm, then ∆ABC is
(a) acute-angled
(b) right-angled
(c) obtuse-angled

Open in App

Solution

(b) right-angled

We have:
$A B^{2} + B C^{2} = 16^{2} + 12^{2} = 256 + 144 = 400 and, A C^{2} = 20^{2} = 400 ∴ A B^{2} + B C^{2} = A C^{2}$

Hence, ∆ABC is a right-angled triangle.

Suggest Corrections

Similar questions

In a $Δ A B C, i f ∠ C = 30^{\circ}, a = 47 c m a n d b = 94 c m$ , then the triangle is

In In $Δ A B C,$ if $8 R^{2} = a^{2} + b^{2} + c^{2},$ then the triangle is

If for a $△ A B C, c o t A . c o t B . c o t C > 0$ then the triangle is

In a triangle $A B C$ , if $tan A + tan + B + tan C = 6$ and $tan A tan B = 2$ , then the triangle is

Join BYJU'S Learning Program