In - ABC- if BD - AC and BC 2-2 AC - CD- then prove that AB - AC-

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Opposite & Adjacent Sides in a Right Angled Triangle

In Δ ABC, if ...

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In ∆ABC, if BD ⊥ AC and BC² = 2 AC . CD, then prove that AB = AC.

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In ΔABC, AB = AC and BD ⊥ AC prove that BD² + CD² = 2AC.CD.

B C^{2} + C D^{2} = 2 A C \times C D

A B C, A B = A C

D

A C

B C^{2} = A C \times C D

B D = B C

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