In ∆ABC, if L and M are points on AB and AC respectively such that LM || BC then ar (LMC) is equal to

ar (MBC)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

¹/₂ ar (LBM)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ar (LOB)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ar (LBM)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
ar (LBM)

In the figure, triangles LBM and LMC are on the same base LM and between the same parallels LM and BC.

Hence, ar (LMC) = ar (LBM)

Suggest Corrections

Similar questions

Q. In a Δ ABC, if L and M are points on AB and AC respectively such that LM || BC. Prove that:

(i) ar (Δ LCM) = ar (Δ LBM)

(ii) ar (Δ LBC) = (Δ MBC)

(iii) ar (Δ ABM) = ar (Δ ACL)

(iv) ar (Δ LOB) = ar (Δ MOC)

Question 6
In $Δ A B C$ , if L and M are the points on AB and AC, respectively such that LM || BC. Prove that $a r (Δ L O B) = a r (Δ M O C)$ .

In a $△ A B C,$ if L and M are points on AB and AC respectively such that LM || BC. Prove that:
$(i) a r (△ L C M) = a r (△ L B M) (i i) a r (△ L B C) = a r (△ M B C) (i i i) a r (△ A B M) = a r (△ A C L) (i v) a r (△ L O B) = a r (△ M O C) .$

Question 6
In $Δ A B C$ , if L and M are the points on AB and AC, respectively such that LM || BC. Prove that $a r (Δ L O B) = a r (Δ M O C)$ .

In a $Δ A B C$ , M and N are points on the sides AB and AC respectively such that BM = CN. If $∠ B = ∠ C$ then show that MN || BC.

Join BYJU'S Learning Program

In ∆ABC, if L and M are points on AB and AC respectively such that LM || BC then ar (LMC) is equal to

The correct option is D ar (LBM)In the figure, triangles LBM and LMC are on the same base LM and between the same parallels LM and BC. Hence, ar (LMC) = ar (LBM)

The correct option is D
ar (LBM)

In the figure, triangles LBM and LMC are on the same base LM and between the same parallels LM and BC.

Hence, ar (LMC) = ar (LBM)