Question

In above problem choose the correct value(s) of $F$ which the blocks $M$ and $m$ remain stationary with respect to $M_0$

• A. $(M_0+M+m)\frac{g}{\mu }$
• B. $\frac{m(M_0+M+m)g}{M-\mu m}$
• C. $(M_0+M+m)\frac{mg}{M}$
• D. None of these

Answer 1

The correct option is B $\frac{m(M_0+M+m)g}{M-\mu m}$

$F=(M_0+M+m)a$

$Ma=T$

$T-\mu ma=mg$

$Ma-\mu ma=mg$

$a=\frac{mg}{M-\mu m}$

Therefore,

$F=(M_0+M+m)\frac{mg}{M-\mu m}$