In above shown circuit diagram, maximum current is passing through

R_{1}, R_{2}, a n d R_{3}

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R_{1}

only

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R_{2}

only

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R_{3}

only

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R_{1} a n d R_{3}

only

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Solution

The correct option is C $R_{1}$ only
The resistance $R_{1}$ is connected directly with the battery in series. Further the resistances $R_{1}$ and $R_{2}$ are connected in parallel with each other and the combination is connected in series with the battery.
The current flowing through $R_{1}$ would split into the two resistances inversely in the ratio of their resistances.
Thus maximum current flows into the resistance $R_{1}$ .

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Similar questions

R_{1} = R_{2} = R_{3} = 10 Ω

R_{1}

R_{2}

R_{1} = R_{2} = R_{3} = 10 Ω

R_{1}

R_{2}

R_{1} = R_{2} = R_{3} = R

\frac{R_{1}}{r_{1}} + \frac{R_{2}}{r_{2}} + \frac{R_{3}}{r_{3}} =

L - C - R

ω

R_{1}, R_{2} a n d R_{3}

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