In above shown figure, a ball of mass m strike the wall with velocity $V$ and rebounds back with same velocity. Calculate the change in momentum.

2 m V

directed to the left

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m V

directed to the left

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Zero

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m V

directed to the right

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2 m V

directed to the right

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Solution

The correct option is A $2 m V$ directed to the left
Initial momentum $= m V$ and after rebound from the wall the final momentum $= - m V$ (negative sign is due to V is opposite to initial V )
So change in momentum $= - m V - (m V) = - 2 m V$
The negative sign indicates it is directed to left.

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In above shown figure, a ball of mass m strike the wall with velocity V and rebounds back with same velocity. Calculate the change in momentum.

The correct option is A 2mV directed to the leftInitial momentum =mV and after rebound from the wall the final momentum =−mV (negative sign is due to V is opposite to initial V )So change in momentum =−mV−(mV)=−2mV The negative sign indicates it is directed to left.

In above shown figure, a ball of mass m strike the wall with velocity $V$ and rebounds back with same velocity. Calculate the change in momentum.

The correct option is A $2 m V$ directed to the left
Initial momentum $= m V$ and after rebound from the wall the final momentum $= - m V$ (negative sign is due to V is opposite to initial V )
So change in momentum $= - m V - (m V) = - 2 m V$
The negative sign indicates it is directed to left.