Question

In above shown figure, two positive point charges +Q are kept, P is the midpoint of line segment joining the charges. If at P , the magnitude of the electric field is E due to only one +Q charge then calculate the net electric field at point P.

• A. 0
• B. $\frac{E}{4}$
• C. $\frac{E}{2}$
• D. 2E
• E. 4E

Answer 1

Answer: (A)

0

The electric field at P due to charge Q at the left is directed towards the charge and due to charge Q at right also directed towards the charge. So field at P due to both charges are equal and opposite direction. Thus, net field will be zero.