You visited us 1 times! Enjoying our articles? Unlock Full Access!

SHM expression

In above show...

Question

In above shown figure, two speaker, $S_{1}$ and $S_{2}$ are kept at 3 m apart. Speakers emit a sound wave of wavelength of m. Emitted waves are in phase with each other. Compare the amplitude of resulting wave at point P and Q if $A_{P}$ and $A_{Q}$ resulted amplitude at point P and Q respectively.

A_{P} < A_{Q}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A_{P} = A_{Q}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A_{P} > A_{Q}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A_{P} < 0, A_{Q} > 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A_{P}

and

A_{Q}

vary with times, so no comparison can be made

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $A_{P} < A_{Q}$
Since the waves travel equal distance in traveling to point Q, they remain in phase with each other, and thus perform a constructive interference to produce maximum amplitude of resulting wave possible.
However in reaching point P, the waves are not exactly in-phase and thus result in amplitude lesser than the maximum.
Thus $A_{P} < A_{Q}$

Suggest Corrections

Similar questions

a_{1}

a_{2}

a_{3}

a_{p}

a_{q}

a_{r}

p, q, r

a_{1}, a_{2}, a_{3}, . . . . . . . . . .

a_{p}, a_{q}, a_{r}

p, q, r

Δ A B C

I

P

Q

A

B I

C I

a_{1}, a_{2}, a_{3}

a_{p}, a_{q}, a_{r}

\frac{a_{q}}{a_{p}} =

In triangle ABC, E and F are the mid points of the sides AC and AB respectively. The altitude AP to BC intersects EF at Q. Then

Join BYJU'S Learning Program