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Common Oxidation States

In acidic med...

Question

In acidic medium, $H_{2} O_{2}$ changes $C r_{2} O_{7}^{2 -}$ to $C r O_{5}$ which has two ( - O - O -) bonds. Oxidation state of Cr in $C r O_{5}$ is

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-10

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Solution

The correct option is C 6
$C r O_{5}$ has butterfly structure having two peroxo bonds.

Peroxo oxygen has -1 oxidation state.
Let oxidation state of Cr be 'x'
$C r O_{5} : x + 4 (- 1) + 1 (- 2) = 0 \Rightarrow x = + 6$

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