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Types of Solution

In acidic med...

Question

In acidic medium, $K M n O_{4}$ oxidises $F e S O_{4}$ solution. Which of the following statements is correct?

10 mL of 1 N

K M n O_{4}

solution oxidises 10 mL of 5 N

F e S O_{4}

solution.

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10 mL of 1 M

K M n O_{4}

solution oxidises 10 mL of 5 M

F e S O_{4}

solution.

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10 mL of 1 M

K M n O_{4}

solution oxidises 10 mL of 1 M

F e S O_{4}

solution.

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10 mL of 1 N

K M n O_{4}

solution oxidises 10 mL of 0.1 M

F e S O_{4}

solution.

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Solution

The correct option is B 10 mL of 1 M $K M n O_{4}$ solution oxidises 10 mL of 5 M $F e S O_{4}$ solution.
$M n O_{4}^{-} + 5 F e^{+ 2} ⟶ M n^{+ 2} + 5 F e^{+ 3}$
$1$ equivalent of $K M n O_{4}$ oxidises $5$ equivalents of $F e S O_{4}$ which seems correctly in option $B$ .

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Similar questions

In an acidic medium, $K M n O_{4}$ oxidises $F e S O_{4}$ solution. Which of the following statements is correct ?

10

ml of

N a H C_{2} O_{4}

solution is neutralised by

10

ml of

0.1 M N a O H

solution.

10

ml of same

N a H C_{2} O_{4}

solution is oxidised by

10

ml of

K M n O_{4}

solution in acidic medium. Hence, molarity of

K M n O_{4}

is :

Q. 10 ml of

K M n O_{4}

Solution is required it completely oxidise acidic solution of 30 ml of 1.5 Volume strength

H_{2} O_{2}

Calculate normality of

K M n O_{4}

Solution :

Q. 20 ml of 0.02 M

K M n O_{4}

was required to completely oxidise 10 ml of oxalic acid solution. What is the molarity of the oxalic acid solution?

10

mL of

H_{2} O_{2}

solution (volume strength

= x

) required

10

mL of

\frac{N}{0.56}

K M n O_{4}

solution in acidic medium. Hence,

x

is:

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In acidic medium, KMnO4 oxidises FeSO4 solution. Which of the following statements is correct?

The correct option is B 10 mL of 1 M KMnO4 solution oxidises 10 mL of 5 M FeSO4 solution.MnO−4+5Fe+2⟶Mn+2+5Fe+31 equivalent of KMnO4 oxidises 5 equivalents of FeSO4 which seems correctly in option B.

In acidic medium, $K M n O_{4}$ oxidises $F e S O_{4}$ solution. Which of the following statements is correct?

The correct option is B 10 mL of 1 M $K M n O_{4}$ solution oxidises 10 mL of 5 M $F e S O_{4}$ solution.
$M n O_{4}^{-} + 5 F e^{+ 2} ⟶ M n^{+ 2} + 5 F e^{+ 3}$
$1$ equivalent of $K M n O_{4}$ oxidises $5$ equivalents of $F e S O_{4}$ which seems correctly in option $B$ .