In adjoining fig two semicircles are drawn on sides AD and BC of a square ABCD- If AB - 10 cm- - 3-14- then the total area of semicircles is -

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In adjoining ...

Question

In adjoining fig two semicircles are drawn on sides $A D$ and $B C$ of a square $A B C D$ . If $A B = 10 cm, (π = 3.14)$ , then the total area of semicircles is :

78.50 {cm}^{2}

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68.50 {cm}^{2}

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70 {cm}^{2}

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70.48 {cm}^{2}

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Solution

The correct option is A $78.50 {cm}^{2}$
Given, diameter $= 10$ cm
Thus radius of the two semicircle $=$ $\frac{10}{2}$ $=$ $5$ cm
Therefore, total area of the two semicircle $= π r^{2}$ $= π (5)^{2}$
$=$ $3.14 \times 25$
$=$ $78.50$ sq.cm

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In adjoining fig two semicircles are drawn on sides AD and BC of a square ABCD. If AB=10 cm,(π=3.14), then the total area of semicircles is :

The correct option is A 78.50 cm2Given, diameter =10 cmThus radius of the two semicircle = 102 = 5 cmTherefore, total area of the two semicircle =πr2 =π(5)2= 3.14×25= 78.50 sq.cm

In adjoining fig two semicircles are drawn on sides $A D$ and $B C$ of a square $A B C D$ . If $A B = 10 cm, (π = 3.14)$ , then the total area of semicircles is :

The correct option is A $78.50 {cm}^{2}$
Given, diameter $= 10$ cm
Thus radius of the two semicircle $=$ $\frac{10}{2}$ $=$ $5$ cm
Therefore, total area of the two semicircle $= π r^{2}$ $= π (5)^{2}$
$=$ $3.14 \times 25$
$=$ $78.50$ sq.cm