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Byju's Answer
Standard XII
Chemistry
Addition of Halogen Acid for Alkynes
In alkaline c...
Question
In alkaline conditions,
K
M
n
O
4
reacts as follows,
2
K
M
n
O
4
+
2
K
O
H
→
2
K
2
M
n
O
4
+
H
2
O
+
[
O
]
Therefore, its equivalent mass will be:
A
31.6
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B
52.7
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C
72.0
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D
158.0
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Solution
The correct option is
D
158.0
Suggest Corrections
1
Similar questions
Q.
In an alkaline medium,
K
M
n
O
4
reacts as follows -
2
K
M
n
O
4
+
2
K
O
H
→
2
K
2
M
n
O
4
+
H
2
O
+
O
Equivalent weight of
K
M
n
O
4
will be:
Q.
In an alkaline medium,
K
M
n
O
4
reacts as follows (At wt. of
K
=
39.09
,
M
n
=
54.94
,
O
=
16.0
):
2
K
M
n
O
4
+
2
K
O
H
→
2
K
2
M
n
O
4
+
H
2
O
+
[
O
]
i) The equivalent weight of
K
M
n
O
4
in alkaline medium is 158.
ii) The number of electrons gained by one molecule of
K
M
n
O
4
in the alkaline medium is 1.
iii) In the alkaline medium,
K
M
n
O
4
acts as a reducing agent.
Select the correct option.
Q.
In neutral medium,
K
M
n
O
4
acts as a powerful oxidizing agent according to the reaction:
2
K
M
n
O
4
+
H
2
O
→
2
M
n
O
2
+
2
K
O
H
+
3
(
O
)
. The change involves
Q.
Assertion :Equivalent mass of
K
M
n
O
4
is equal to one-third of its molecular mass when it acts as an oxidising agent in an alkaline medium. Reason: Oxidation number of
M
n
is +7 in
K
M
n
O
4
.
Q.
Equivalent mass of
K
M
n
O
4
in alkaline medium is
52.66
or
M
3
.
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