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In alkaline m...

Question

In alkaline medium $C l O_{2}$ oxidises $H_{2} O_{2}$ to $O_{2}$ and itself gets reduced to $C l^{-}$ . How many moles of $H_{2} O_{2}$ are oxidised by $1$ mole of $C l O_{2}$ ?

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Solution

The balanced chemical equation is:
$2 C l O_{2} + 5 H_{2} O_{2} + 2 O H^{-} \to 2 C l^{-} + 5 O_{2} + 6 H_{2} O$
$2$ moles of $C l O_{2} \equiv 5$ moles of $H_{2} O_{2}$
$∴$ $1$ moles of $C l O_{2} \equiv 2.5$ moles of $H_{2} O_{2}$

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