wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In AM wave, total power of side bands is given by:

A
Ps=Ec24R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Ps=4Ec2R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Ps=m2Ec24R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Ps=Ec24m2R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Ps=m2Ec24R
power of side band Ps is given by

Ps=meE2rmsR

Here Erms=Ec2 and me=m2

Putting value we get :

Ps=m2E2c4R

Hence option C is correct

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Building a Wave
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon