In ammoniacal solution, dichromate in presence of $H_{2} O_{2}$ forms $(N H_{3})_{3} C r O_{4}$ in which Cr is in +IV state. The structure is pentagonal bipyramid. If true enter 1 else 0.

True

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False

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Solution

The correct option is A True
In ammoniacal solution, dichromate in presence of $H_{2} O_{2}$ forms (NH3)3CrO4.
Now, the oxidation state of $C r$ , is +4.

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