In an a.c. circuit, the instantaneous e.m.f. and current are given by e=100sin30t i=20sin(30t−π4) In one cycle of a.c., the average power consumed by the circuit (in watts) and the wattless current (in amperes) are respectively (Assume SI units)
A
50,0
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B
50,10
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C
1000√2,10
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D
50√2,0
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Solution
The correct option is C1000√2,10 Average power consumed by the circuit Pavg=Vrms.Irms.cosϕ Pavg=100√2.20√2.cos45∘ Pavg=1000√2W
Wattless current =Ivsin45∘ ∴iwattless=20√2×sin45∘ =20√2×1√2=10A