In an a. c. circuit, the instantaneous e.m.f. and current are given by e=100sin30t i=20sin(30t−r/4). In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively.
A
50√2,0
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B
50,0
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C
50,10
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D
1000√2,10
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Solution
The correct option is D1000√2,10 e=100sin30t i=20sin(30t−π4) Pav=ermsirmscosϕ =100√2⋅20√2⋅1√2=1000√2W
Wattless current =I0sinϕ√2=20√2⋅1√2=10A