In an a-c- circuit V and I are given by V-100sin100tvolts and I-100sin100t-3mA- The power dissipated in the circuit is

The correct option is D 2.5 watt P=V_r.m.s×I_r.m.s× #160;cosϕ #160; #160; #160; =12× 100× (100×10^ 3)cosπ/3 #160; =2.5W ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Power in an AC Circuit

In an a.c. ci...

Question

In an a.c. circuit $V$ and $I$ are given by $V = 100 s i n (100 t) v o l t s$ and $I = 100 s i n (100 t + π / 3) m A$ . The power dissipated in the circuit is

10^{4}

watt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10

watt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5

watt

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.0

watt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $2.5$ watt
$P = V_{r . m . s} \times I_{r . m . s} \times cos ϕ$
$= \frac{1}{2} \times 100 \times (100 \times 10^{- 3}) cos π / 3 = 2.5 W$

Suggest Corrections

Similar questions

Q. If

V = 100 sin 100 t

volt, and

I = 100 sin (100 t + \frac{π}{6}) A

. then find the watt less power in watt?

The voltage and the current of an $a . c$ circuit are $V = 100 sin (100 t)$ volt and $i = 100 sin (100 t + π / 3) m A$ receptively. The power dissipated in the circuit is:

In a A.C. circuit, V and I are given by V = 100sin (100t) volt, I = 100 sin $(100 t + \frac{π}{3})$ A then the power dissipated in the circuit is

Q. In an AC circuit, the potential difference

V

and current

I

are given respectively by

V = 100 sin (100 t) V

and

I = 100 sin (100 t + \frac{π}{3}) m A

The power dissipated in the circuit will be

Q. In LCR series circuit, an alternating e.m.f. 'e' and current 'i' are given by the equations

e = 100 sin (100 t)

volt,

i = 100 sin (100 t + \frac{π}{3}) m A

. The average power dissipated in the circuit will be.

Join BYJU'S Learning Program

In an a.c. circuit V and I are given by V=100sin(100t)volts and I=100sin(100t+π/3)mA. The power dissipated in the circuit is

The correct option is D 2.5 wattP=Vr.m.s×Ir.m.s×cosϕ =12×100×(100×10−3)cosπ/3=2.5W

In an a.c. circuit $V$ and $I$ are given by $V = 100 s i n (100 t) v o l t s$ and $I = 100 s i n (100 t + π / 3) m A$ . The power dissipated in the circuit is

The correct option is D $2.5$ watt
$P = V_{r . m . s} \times I_{r . m . s} \times cos ϕ$
$= \frac{1}{2} \times 100 \times (100 \times 10^{- 3}) cos π / 3 = 2.5 W$