In an a.c., circuit with phase voltage $V$ and current $I$ , the power dissipated is

\frac{V I}{2}

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\frac{V I}{\sqrt{2}}

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V I

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V I c o s θ

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Solution

The correct option is C $V I c o s θ$
$P = V I c o s θ$ . So power dissipation depends upon $V$ , $I$ and $c o s (θ)$ where $θ$ is the phase angle between voltage and current.
So, the correct option is $(D)$

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Similar questions

The voltage and the current of an $a . c$ circuit are $V = 100 sin (100 t)$ volt and $i = 100 sin (100 t + π / 3) m A$ receptively. The power dissipated in the circuit is:

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.
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In an a.c., circuit with phase voltage V and current I, the power dissipated is

The correct option is C VIcosθP=VIcosθ. So power dissipation depends upon V, I and cos(θ) where θ is the phase angle between voltage and current.So, the correct option is (D)

In an a.c., circuit with phase voltage $V$ and current $I$ , the power dissipated is

The correct option is C $V I c o s θ$
$P = V I c o s θ$ . So power dissipation depends upon $V$ , $I$ and $c o s (θ)$ where $θ$ is the phase angle between voltage and current.
So, the correct option is $(D)$