In an $A . P - 10, - 6, - 2, 2, . . . .20 t h$ term is

66

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- 66

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77

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Solution

The correct option is A $66$
$\begin{matrix} - 10, - 6, - 2, 2...2 t h t e r m f i r s t t e r m = - 10 c o m m o n d i f f e r e n c e = 4 \Rightarrow T_{20} = - 10 + 19 \times 4 \Rightarrow T_{20} = - 10 + 76 = 66 \end{matrix}$

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