In an A.P., first term is 1, last term is 11 and sum of n terms is 36, then n =

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
6

$\frac{n}{2}$ (2a + (n-1)d) = 36,

here a = 1,

a + (n - 1)d = 11

$\frac{n}{2}$ (a + a + (n - 1)d) = 36

$\frac{n}{2}$ (1 + 11) = 36

$\Rightarrow$ n = 6

Suggest Corrections

Similar questions

In an A.P., first term is 1, last term is 11 and sum of n terms is 36, then n=

n

476,

= 20, n = 17

In an A.P., the first term is 22 and the nth term is -11. If the sum to first n terms is 66, then what is the value of n?

1

11

36

The first and last term of an ap are 1 and 11 if the sum of its terms is 36 then a = ______,d=_____,n=_____&a_n=_________

Join BYJU'S Learning Program