In an A.P. first term is $7$ . Common difference is $3$ find the $n^{t h}$ term of an $A P$ .

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Solution

Given the first term of a $A P$ is $a = 7$

common difference is $d = 3$

As we know that

$n^{t h}$ term of an $A P$ is $a + (n - 1) d$

So $n^{t h}$ term is $7 + (n - 1) (3) = 7 + 3 n - 3 = 4 + 3 n$

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In an A.P. first term is 7. Common difference is 3 find the nth term of an AP.

Given the first term of a AP is a=7common difference is d=3As we know that nth term of an AP is a+(n−1)dSo nth term is 7+(n−1)(3)=7+3n−3=4+3n

In an A.P. first term is $7$ . Common difference is $3$ find the $n^{t h}$ term of an $A P$ .

Given the first term of a $A P$ is $a = 7$

common difference is $d = 3$

As we know that

$n^{t h}$ term of an $A P$ is $a + (n - 1) d$

So $n^{t h}$ term is $7 + (n - 1) (3) = 7 + 3 n - 3 = 4 + 3 n$