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Question

In an A.P. if d=2, T22=39, find a

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Solution

We know that the formula for the nth term is tn=a+(n1)d, where a is the first term, d is the common difference.

It is given that the nth term is t22=39 and the difference is d=2, therefore,

tn=a+(n1)d39=a+(221)(2)39=a+(21×2)39=a42a=39+42=3

Hence, a=3


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