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Question

In an A.P if sum of its n first terms is 3n2+5n and its kth term is 164, find the value of k.

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Solution

Given Sn=5n2+11n
We use Sn1=5(n1)2+11(n1)
Sn1=5(n2+12n)+11n11
Sn1=5n210n+5+11n11
Sn1=5n2+n6
Now
Tn=SnSn1=5n2+11n5n2n+6
[Tn=10n+6]

1216717_1370203_ans_e6d5c16f7a90491ab36ea33590f2556b.JPG

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