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Question

In an A.P., if the 5th and 12th terms are 30 and 65 respecitvely, what is the sum of first 20 terms?

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Solution

a+4d=30

a+11d=65

a+11d - a-4d=35

7d=35

d=5

a+20=30

a=10

s20 = n/2(2a+(n-1)d)

=20/2(20 + 95)

= 10(115)

= 1150


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