In an A.P., if the 5th and 12th terms are 30 and 65 respecitvely, what is the sum of first 20 terms?
a+4d=30
a+11d=65
a+11d - a-4d=35
7d=35
d=5
a+20=30
a=10
s20 = n/2(2a+(n-1)d)
=20/2(20 + 95)
= 10(115)
= 1150