In an A.P of which 1 is the first term if the sum of the first p terms is zero, then the sum of the (p+q) terms is
A
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B
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C
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D
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Solution
The correct option is A Let d be the common difference ⇒Sp=0⇒p2[2+(p−1)d]=0⇒21−p The sum of the (p+ q)terms = Sp+q=(p+q)2[2+(p+q−1)d] =(p+q)2[2+(p+q−1)21−p]=(p+q)1−p[1−p+p+q−1]=q(p+q)1−p