In an $A . P .$ , show that $a_{m + n} + a_{m - n} = 2 a_{m}$ ?

Open in App

Solution

$(a_{m + n}) + (a_{m - n}) = a_{m} [(1 + n) + (1 - n)]$

$= a_{m} (1 + n + 1 - n)$

$= a_{m} (1 + 1)$

$= a_{m} (2)$

$= {2 a}_{m}$

Suggest Corrections

Similar questions

⟨ a_{n} ⟩

a_{m + n +} + a_{m - n} = 2 a_{m}

If the sequence $< a_{n} >$ is an A.P., show that $a_{m + n} + a_{m - n} = 2 a_{m}$

a^{m}

a^{n}

(1 + a)^{m + n}

l i m x \to a \frac{x^{m} - a^{m}}{x^{n} - a^{n}} = \frac{m}{n} a^{m - n}

Join BYJU'S Learning Program