Question

In an A.P. the first and fourth terms are $5$ and $17$. Then find the tenth term of the A.P.

Answer 1

Given the first term of the A.P. is $5$.

Let the common difference of the A.P. be $d$.

Then the fourth term of the A.P. is

$5+(4-1)d=17$

or, $3d=12$

or, $d=4$.

Then the tenth term is $5+(10-1)4=5+27=32$.