MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Condensation

In an absorpt...

Question

In an absorption type refrigeration system, heating in generator, refrigeration in evaporator and cooling by cooling water in condenser takes place at $95^{\circ} C$ , $- 5^{\circ} C$ and $30^{\circ} C$ respectively. The maximum COP of the system.

A

1.35

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

1.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1.53

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

3.35

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1.35
$(C O P)_{m a x} = \frac{T_{E} (T_{G} - T_{O})}{T_{G} (T_{O} - T_{E})} = \frac{268 (368 - 303)}{368 (303 - 268)} = 1.35$

Suggest Corrections

thumbs-up

0

Similar questions

Q. An absorption refrigeration system having evaporator temperature of -5°C and ambient temperature of 25°C. The heat is supplied to generator from steam at 0.1 MPa, 0.95 quality. The saturated temperature of steam at 0.1 MPa is 100°C and

h_{f g} = 2000 k J / k g .

What is the steam flow rate required if the actual COP is 80% of maximum COP and the refrigerator effect is 60 kW?

Q. A food storage chamber requires a refrigeration system of 12 tons capacity when evaporator temperature is

- 8^{\circ} C

and condenser temperature is

30^{\circ} C

. The system uses R-12 as refrigerant with properties given below. The refrigerant is subcooled by

5^{\circ} C

before entering the throttle valve and vapour is superheated in the evaporator itself by

6^{\circ} C

before entering the compressor. What is the COP of cycle?

Q. In a 10 kW cooling capacity refrigeration system operating on VCRS, the refrigerant enters the evaporator with an enthalpy of 80 kJ/kg and leaves with an enthalpy of 180 kJ/kg. The enthalpy of the refrigerant after compression is 220 kJ/kg. The rate of heat transfer at the condenser is

Q. The following data is for an absorption refrigeration system:
Temperature of evaporator = -15°C
Ambient temperature = 33°C
Actual COP = 35% of maximum COP
Load = 25 tonnes
Heat is supplied to the generator by condensing steam at 0.3 MPa, 80% quality.
What is the flow rate of the steam required for this purpose?

Take

T_{s a t} = 130^{\circ} C, h_{f g} = 2250 k J / k g, a t 0.3 M P a .

Q. If the heat rejection ratio of condenser in refrigeration system is

1.2,

the COP of the plant is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Combination of Methods

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard VI Chemistry

Join BYJU'S Learning Program

CrossIcon