Question

In an AC circuit an alternating voltage $200\sqrt{2}sin100t$ volts is connected to a capacitor of capacity $1\mu F$. The r.m.s. value of the current in the circuit is:

• A. 10 mA
• B. 100 mA
• C. 200 mA
• D. 20 mA

Answer 1

The correct option is D 20 mA

$X_C=\frac{1}{\omega C}=\frac{1}{100\times {10}^{-6}}={10}^4\Omega$

$V_{rms}=\frac{V_0}{\sqrt{2}}=200volt$

$I_{rms}=\frac{V_{rms}}{X_C}=\frac{200}{{10}^4}=20\times {10}^{-3}A=20mA$