In an ac circuit an alternating voltage e=200√2sin100t volts is connected to a capacitor of capacity 1μF.The r.m.s. value of the current in the circuit is :
A
20mA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A20mA Given: e=200√2sin100t v C=1μF. irms=VrmsXC=200(1100×10−6) irms=2×10−2=20mA.
Hence, option (D) is correct.