In an AC circuit, the instantaneous emf and current are given by e=100sin30t,i=20sin(30t−π4). In one cycle of AC, the average power consumed by the circuit in watt and the wattless current in amperes are, respectively –
A
50,0
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B
50,0
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C
1000√2,10
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D
50√2,0
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Solution
The correct option is C1000√2,10 Pav=ErmsIrmscosϕ=(E0√2)(I0√2)cos45∘ =100√2×20√2×1√2 =1000√2 watt
wattless current Irmssinϕ =I0√2sinϕ =20√2sin45∘ =20√2×1√2 =10 A