In an ac circuit the instantaneous values of current and applied voltage are respectively i-2Ampsin250 -s-1t and -10Vsin-250 -s-1t-3- Find the power drawn from the source at t-23ms

We know that #160;instantaneous power = VI V = 10sin(250 #960; ×23 + #960;3) V = 10sin(501 #960;3) and #160; i = 2sin(250 #960;×23) ...

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Inductors in Circuits

In an ac circ...

Question

In an ac circuit the instantaneous values of current and applied voltage are respectively $i = 2 (A m p) sin (250 π s^{- 1}) t$ and $ϵ = (10 V) sin [(250 π s^{- 1}) t + \frac{π}{3}]$ . Find the power drawn from the source at $t = \frac{2}{3} m s$

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i = 2 (A m p) sin (250 π s^{- 1}) t

ϵ = (10 V) sin [(250 π s^{- 1}) t + \frac{π}{3}]

t = \frac{2}{3} m s

i = \frac{1}{\sqrt{2}} sin (100 π t)

E = \frac{1}{\sqrt{2}} sin (100 π t + π / 3)

i = 4 sin ω t

V = 100 cos (ω t - \frac{π}{3})

= 200 sin (ω t - \frac{π}{3});

= 10 sin (ω t + \frac{π}{6})

i = 100 sin 314 t

e = 200 sin (314 t + \frac{π}{3}) V

1 Ω

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