In an AC circuit- the voltage V and the current I are given by V -100 sin 100 - t volt and I -100 sin-100 t -3- mA- The power dissipated in the circuit isA- ZeroB- 10 WC- 5 WD- 2-5 W

The correct option is D 2.5W P=V_rI_r cos φ = V_0/√(2)I_0/√(2)cos ϕ=100/√(2)100/√(2)10^ 3 cosπ/3=10/21/2=2.5W ...

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Byju's Answer

Standard XII

Physics

Power in an AC Circuit

In an AC circ...

Question

In an AC circuit, the voltage V and the current I are given by $V = 100 s i n (100 π t) v o l t a n d I = 100 s i n [100 t + \frac{π}{3}] m A$ , The power dissipated in the circuit is

Zero

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10W

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2.5W

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Solution

The correct option is D
2.5W

$P = V_{r} I_{r} c o s φ = \frac{V_{0}}{\sqrt{2}} \frac{I_{0}}{\sqrt{2}} c o s ϕ = \frac{100}{\sqrt{2}} \frac{100}{\sqrt{2}} 10^{- 3} c o s \frac{π}{3} = \frac{10}{2} \frac{1}{2} = 2.5 W$

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In an AC circuit, the voltage V and the current I are given by V=100 sin(100 π t) volt and I=100 sin [100t+π3]mA , The power dissipated in the circuit is

The correct option is D 2.5W P=VrIr cos φ=V0√2I0√2cos ϕ=100√2100√210−3 cosπ3=10212=2.5W

In an AC circuit, the voltage V and the current I are given by $V = 100 s i n (100 π t) v o l t a n d I = 100 s i n [100 t + \frac{π}{3}] m A$ , The power dissipated in the circuit is

The correct option is D
2.5W

$P = V_{r} I_{r} c o s φ = \frac{V_{0}}{\sqrt{2}} \frac{I_{0}}{\sqrt{2}} c o s ϕ = \frac{100}{\sqrt{2}} \frac{100}{\sqrt{2}} 10^{- 3} c o s \frac{π}{3} = \frac{10}{2} \frac{1}{2} = 2.5 W$