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Ohm's Law

in an ac prod...

Question

in an ac produces same heat as that produced by a steady current of 4 ampere then the peak value of current is

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Solution

$L e t t h e h e a t p r o d u c e d b y s t e a d y c u r r e n t b e H = I^{2} R t a n d t h e h e a t p r o d u c e d b y A . C . c u r r e n t i s H = \frac{{i_{0}}^{2}}{2} R t b u t I = 4 A, s o, \frac{{i_{0}}^{2}}{2} R t = I^{2} R t = 4^{2} R t o r {i_{0}}^{2} = 16 \times 2 o r i_{0} = 4 \sqrt{2} = 4 \times 1.414 = 5.656 A .$

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