wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In an acute angled triangle ABC, if tan(A+BC)=1 and, sec(B+CA)=2, find the value of A, B and C.

Open in App
Solution

tan(A+BC)=1=tan45o
A+BC=45o .........(1)
sec(B+CA)=2=sec60o
B+CA=60o ........(2)
Solving equations 1 and 2, we get,
B=5212o

CA=712o ........(3)

In ABC,
A+B+C=180o
C+A=12712o ........(4)

Solving equations 3 and 4, we get,
A=60o and C=6712o

Hence, A=60o,B=5212o and C=6712o

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon