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Question

In an acute-angled triangle, cotBcotC+cotAcotC+cotAcotB=

A
1
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B
0
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C
1
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D
2
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Solution

The correct option is C 1
cotBcotC+cotA+cotC+cotAcotB
Since A+B+C=π
so, A+B=πC
cot(A+B)=cot(πC)
cotAcotB1cotB+cotA=cotC
cotAcotB+cotBcotC+cotAcotC=1

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