Question

In an adsorption experiment, a graph between log(x/m) versus log p was found to be linear with a slope of $1.0$. The intercept on the log axis was found to be $\mathrm{0.3010.}$ what will be the amount of gas adsorbed per gram of charcoal under a pressure of $0.5$ atmosphere.

Answer 1

$log\left(\frac{x}{m}\right)=\frac{1}{n}logp+logk$
$\frac{1}{n}=1.0logk=0.3010p=0.5$
$\frac{x}{m}=p^{1/n}.k$
$\Rightarrow \frac{x}{m}=2\times (0.5{)}^{1/1}=1$